remquo Function

Calculates x REM y as a double precision value.

Include

<math.h>

Prototype

double remquo(double x, double y, int * quo);

Arguments

x

a double precision floating-point value

y

a double precision floating-point value

quo

a pointer to an int object that can hold the quotient

Return Value

Returns the same remainder as remainder function, being x − ny, where n is the nearest integer to the exact value of x/y. In the object pointed to by quo is stored a quotient with the same sign as x/y, and whose magnitude is congruent modulo 2m to the magnitude of the integral quotient of x/y, where m is an implementation-defined integer greater than or equal to 3. The rounding mode is ignored.

Remarks

If the remainder is 0, its sign shall be the same as that of x.

Example

#include <math.h>
#include <stdio.h>

int main(void)
{
  double x, y, z;
  int q;

  x = 7.0;
  y = 3.0;
  z = remquo(x, y, &q);
  printf("%f REM %f is %f with quotient %d\n", x, y, z, q);
}

Example Output

7.000000 REM 3.000000 is 1.000000