Append a specified number of characters from the source string to the destination string.
Include
<string.h>
Prototype
char *strncat(char *s1, const char *s2, size_t
n);
Arguments
s1
s2
n
Return Value
Returns a pointer to the destination string.
Remarks
This function appends up to n
characters (a null character
and characters that follow it are not appended) from the source string to the end of the
destination string. If a null character is not encountered, then a terminating null
character is appended to the result. If the strings overlap, the behavior is
undefined.
Example
#include <string.h>
#include <stdio.h>
int main(void)
{
char buf1[50] = "We're here";
char buf2[50] = "Where is the time?";
char buf3[50] = "Why?";
printf("buf1 : %s\n", buf1);
printf("\t(%d characters)\n\n", strlen(buf1));
printf("buf2 : %s\n", buf2);
printf("\t(%d characters)\n\n", strlen(buf2));
printf("buf3 : %s\n", buf3);
printf("\t(%d characters)\n\n\n", strlen(buf3));
strncat(buf1, buf2, 6);
printf("buf1 after strncat of 6 characters "
"of buf2: \n\t%s\n", buf1);
printf("\t(%d characters)\n", strlen(buf1));
printf("\n");
strncat(buf1, buf2, 25);
printf("buf1 after strncat of 25 characters "
"of buf2: \n\t%s\n", buf1);
printf("\t(%d characters)\n", strlen(buf1));
printf("\n");
strncat(buf1, buf3, 4);
printf("buf1 after strncat of 4 characters "
"of buf3: \n\t%s\n", buf1);
printf("\t(%d characters)\n", strlen(buf1));
}
Example Output
buf1 : We’re here
(10 characters)
buf2 : Where is the time?
(18 characters)
buf3 : Why?
(4 characters)
buf1 after strncat of 6 characters of buf2:
We’re hereWhere
(16 characters)
buf1 after strncat of 25 characters of buf2:
We’re hereWhere Where is the time?
(34 characters)
buf1 after strncat of 4 characters of buf3:
We’re hereWhere Where is the time?Why?
(38 characters)