# sqrtl Function

Calculates the square root of a long double precision floating-point value.

Include

<math.h>

Prototype

long double sqrtf(long double x);

Argument

 x a non-negative floating-point value

Return Value

Returns the non-negative square root of x.

Remarks

If x is less than 0, a domain error will occur and errno will be set to EDOM.

Example

See the notes at the beginning of this chapter or section for information on using printf() or scanf() (and other functions reading and writing the stdin or stdout streams) in the example code.

#include <math.h>
#include <stdio.h>
#include <errno.h>

int main(void)
{
double x;

errno = 0;
x = sqrtl(0.0F);
if (errno)
perror("Error");
printf("The square root of 0.0F is %Lf\n", x);

errno = 0;
x = sqrtl(9.5F);
if (errno)
perror("Error");
printf("The square root of 9.5F is %Lf\n", x);

errno = 0;
x = sqrtl(-25.0F);
if (errno)
perror("Error");
printf("The square root of -25F is %Lf\n", x);
}

Example Output

The square root of 0.0F is 0.000000
The square root of 9.5F is 3.082207
Error: domain error
The square root of -25F is nan