13.1 Integral Promotion
When there is more than one operand to an operator, they typically must be of exactly the same type. The compiler will automatically convert the operands, if necessary, so they do have the same type. The conversion is to a “larger” type so there is no loss of information; however, the change in type can cause different code behavior to what is sometimes expected. These form the standard type conversions.
Prior to these type conversions, some operands are unconditionally converted to a larger type, even if both operands to an operator have the same type. This conversion is called integral promotion and is part of Standard C behavior. The MPLAB XC32 C/C++ Compiler performs these integral promotions where required, and there are no options that can control or disable this operation. If you are not aware that the type has changed, the results of some expressions are not what would normally be expected.
Integral promotion is the implicit conversion of enumerated types,
signed
or unsigned
varieties of
char
, short int
or bit field types to either
signed int
or unsigned int
. If the result of the
conversion can be represented by an signed int
, then that is the
destination type, otherwise the conversion is to unsigned int
.
Consider the following example:
unsigned char count, a=0, b=50;
if(a - b < 10)
count++;
The unsigned char
result of a - b
is 206 (which is not
less than 10), but both a
and b
are converted to
signed int
via integral promotion before the subtraction takes
place. The result of the subtraction with these data types is -50 (which is less
than 10) and hence the body of the if()
statement is executed.
If the result of the subtraction is to be an unsigned
quantity, then
apply a cast. For example:
if((unsigned int)(a - b) < 10)
count++;
The comparison is then done using unsigned int
, in this case, and the
body of the if()
would not be executed.
Another problem that frequently occurs is with the bitwise compliment operator,
~
. This operator toggles each bit within a value. Consider the
following code:
unsigned char count, c;
c = 0x55;
if( ~c == 0xAA)
count++;
If c
contains the value 0x55, it often assumed that ~c
will produce 0xAA, however the result is 0xFFFFFFAA and so the comparison in the above
example would fail. The compiler may be able to issue a mismatched comparison error to
this effect in some circumstances. Again, a cast could be used to change this
behavior.
The consequence of integral promotion as illustrated above is that operations are not
performed with char
-type operands, but with int
-type
operands. However there are circumstances when the result of an operation is identical
regardless of whether the operands are of type char
or
int
. In these cases, the MPLAB XC32 C/C++ Compiler will not perform
the integral promotion so as to increase the code efficiency. Consider the following
example:
unsigned char a, b, c;
a = b + c;
Strictly speaking, this statement requires that the values of b
and
c
should be promoted to unsigned int
, the addition
performed, the result of the addition cast to the type of a
, and then
the assignment can take place. Even if the result of the unsigned int
addition of the promoted values of b
and c
was
different to the result of the unsigned char
addition of these values
without promotion, after the unsigned int
result was converted back to
unsigned char
, the final result would be the same. If an 8-bit
addition is more efficient than a 32-bit addition, the compiler will encode the
former.
If, in the above example, the type of a
was unsigned
int
, then integral promotion would have to be performed to comply with the
ANSI C standard.