5.2 Bootstrap Capacitor Selection

The initial step in determining the value of the bootstrap capacitor is to determine the minimum voltage drop (ΔVBS) that can be guaranteed when the high side device is turned on. In other words, the minimum gate-source voltage (VGSmin) must be greater than the UVLO of the high side circuit, specifically VBSUV– level. Therefore, if VGSmin is the minimum gate-source voltage such that:

VGSmin > VBSUV–

Then:

V B S = V C C - V F - V G S m i n - V X

Where:

  • VCC is the supply voltage to the MCP14H2304
  • VF is the voltage drop across the bootstrap diode (DBS)
  • VX is the voltage drop across the MOSFET

VX is calculated as the current seen across low side MOSFET multiplied by its RDSON and is simply VCE-ON at the specify output current if an IGBT were used instead.

In addition to the voltage drops across these components, other factors that cause VBS to drop are leakages, charge required to turn on the power devices, and duration of the high-side on time. The total charge (QT) required by the gate driver then equals:

Q T = Q G + Q L S + I L K N × t H O N

Where:

  • QG is the gate charge of power device
  • QLS is the level shift charge required per cycle
  • tHON is the high-side ON time
  • ILKN is the sum of all leakages that include:
    • IGSS/IGES: Gate-source leakage of the power device
    • ILK_DB: Bootstrap diode leakage
    • ILK_IC: Offset supply leakage of HVIC
    • IQBS: Quiescent current for high side supply

QLS is not listed in the datasheet. Depending on the process technology, it could range anywhere from 3-20 nC for 500V to 1200V process respectively. Assuming a value of 10 nC for Microchip’s 600V process should be sufficient with added margin.

From the basic equation, then the minimum bootstrap capacitor is calculated as:

C B m i n Q T V B S