13.24.2 Bootstrap Capacitor
The high-side driver bootstrap capacitor needs to power the high-side driver and gate for 1/3 of the motor electrical period for a 3-phase BLDC motor operating in Six-Step mode.
Let:
MOSFET Driver Current = 300 mA
PWM Period = 50 µs (20 kHz) Minimum Duty Cycle = 1% (500 ns) Maximum Duty Cycle = 99% (49.5 µs)
VIN = 12V
Minimum Gate Drive Voltage = 8V (VGS)
Total Gate Charge = 130 nC (80A MOSFET)
Allowable VGS Drop (VDROP) = 3V
Switch RDSON = 100 mW Driver Internal Bias Current = 20 µA (IBIAS)
Solve for the smallest capacitance that can supply:
- 130 nC of charge to the MOSFET gate
- 1 Megohm gate source resistor current
- Driver bias current and switching losses
QMOSFET = 130 nC
QRESISTOR = [(VGS/R) × TON]
QDRIVER = (IBIAS × TON)
TON = 49.5 µs (99% DC) for worst case
QRESISTOR = QRESISTOR
QDRIVER = 20 µA × 49.5 µs = 0.99 nC
Sum all of the energy requirements:
- C = (QMOSFET + QRESISTOR +
QDRIVER)/VDROP
- C = (130 nC + 0.594 nC + 0.99 nC)/3V
- C = 43.86 nF
Choose a bootstrap capacitor value that is larger than 43.86 nF.
